First find the no of odd days between January 1 2005 and January 1 2004

2004 is leap year so it has the odd days 2

So Thursday+2 days (Friday +Saturday)

So it will be Saturday

Aptitude Quantitative Question Answer

Another Method

January 1 2005=(2004+2005 January 1)

2004=(2000+4)

2000 it has 0 odd days-----------------------1

4 it has 1 leap year and 3 ordinary year

S 2+3=5 odd days-------------------------2

January 1 in 2005

it has one odd days=1---------------3

Finally equation from 1,2,3, no of odd days are =0+5+1=6

6th is Saturday—Interview important aptitude question

2004 is leap year so it has the odd days 2

So Thursday+2 days (Friday +Saturday)

So it will be Saturday

Aptitude Quantitative Question Answer

Another Method

January 1 2005=(2004+2005 January 1)

2004=(2000+4)

2000 it has 0 odd days-----------------------1

4 it has 1 leap year and 3 ordinary year

S 2+3=5 odd days-------------------------2

January 1 in 2005

it has one odd days=1---------------3

Finally equation from 1,2,3, no of odd days are =0+5+1=6

6th is Saturday—Interview important aptitude question

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