What was the day of the week on 16th July 1776?

1776 July 16th =(1775year+period of 1 January to 16 July 1776)

(First find the nearest leap year (because it contain 0 odd days-see the formula)

1775=1600+175 years-equation 1

175=100+75 years –equation 2

From equation 1

1600 year contain 0 odd days

And 175 year 100+75

100 year contain 5 odd days

75 years =(18 leap year and 67 ordinary year so)=(18*2+57)

Which is equal to 93 then it will give 2 odd days

So total no of odd days=0+5+2=7 so seven odd days is equal to 1 weak so odd days Is 0

From 1776 January 1 to July 16th 1776

Jan=31 February =29 march =31 April =30 June=31 July=16

So total no of days=198 odd days =2 days

So the day is Tuesday see the formula

What was the day of the week on 16th April 2000

2000=(1999+2000 January to April 16th)

1999=(1600+399)

399=(300+99)

99=24 leap year and 75 ordinary days

So (24*2+75)=123 days there odd days are 4---------------------------1

300 it has 1 odd days---------------------------------2

1600 it has 0 odd days -----------------------------3

2000 January to 16th April

January=31 February=29 march=31 April=16

So 31+29+30+16=107 it has 2 odd days-----------4

Finally form 1,2,3,4 odd days are=4+1+0+2=7

7 odd days become one week so it has 0 odd days so there date is Sunday –Interview important Aptitude Question

1776 July 16th =(1775year+period of 1 January to 16 July 1776)

(First find the nearest leap year (because it contain 0 odd days-see the formula)

1775=1600+175 years-equation 1

175=100+75 years –equation 2

From equation 1

1600 year contain 0 odd days

And 175 year 100+75

100 year contain 5 odd days

75 years =(18 leap year and 67 ordinary year so)=(18*2+57)

Which is equal to 93 then it will give 2 odd days

So total no of odd days=0+5+2=7 so seven odd days is equal to 1 weak so odd days Is 0

From 1776 January 1 to July 16th 1776

Jan=31 February =29 march =31 April =30 June=31 July=16

So total no of days=198 odd days =2 days

So the day is Tuesday see the formula

What was the day of the week on 16th April 2000

2000=(1999+2000 January to April 16th)

1999=(1600+399)

399=(300+99)

99=24 leap year and 75 ordinary days

So (24*2+75)=123 days there odd days are 4---------------------------1

300 it has 1 odd days---------------------------------2

1600 it has 0 odd days -----------------------------3

2000 January to 16th April

January=31 February=29 march=31 April=16

So 31+29+30+16=107 it has 2 odd days-----------4

Finally form 1,2,3,4 odd days are=4+1+0+2=7

7 odd days become one week so it has 0 odd days so there date is Sunday –Interview important Aptitude Question

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